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Convert [Millielectron Volt] to [Liter Atmosphere], (meV to l atm)

ENERGY


18800 Millielectron Volt
= 2.9727099925981E-20 Liter Atmosphere
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Category: energy
Conversion: Millielectron Volt to Liter Atmosphere
The base unit for energy is joules (Non-SI/Derived Unit)
[Millielectron Volt] symbol/abbrevation: (meV)
[Liter Atmosphere] symbol/abbrevation: (l atm)

How to convert Millielectron Volt to Liter Atmosphere (meV to l atm)?
1 meV = 1.5812287194671E-24 l atm.
18800 x 1.5812287194671E-24 l atm = 2.9727099925981E-20 Liter Atmosphere.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Millielectron Volt (meV) is equal to 1.60218E-22 joules, while 1 Liter Atmosphere (l atm) = 101.325 joules.
18800 Millielectron Volt to common energy units
18800 meV = 3.0120984E-18 joules (J)
18800 meV = 3.0120984E-21 kilojoules (kJ)
18800 meV = 7.1990879541109E-19 calories (cal)
18800 meV = 7.1990879541109E-22 kilocalories (kcal)
18800 meV = 18.8 electron volt (eV)
18800 meV = 8.36694E-22 watt hour (Wh)
18800 meV = 0.69088882282996 atomic unit of energy (au)
18800 meV = 7.1990879541109E-28 tons of TNT (tTNT)
18800 meV = 2.2216097697386E-18 foot pound force (ft lbf)
18800 meV = 3.0120984E-11 ergs (ergs)
(Millielectron Volt) to (Liter Atmosphere) conversions

Millielectron Volt to random (energy units)

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