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Convert [Millielectron Volt] to [Liter Atmosphere], (meV to l atm)

ENERGY


28 Millielectron Volt
= 4.4274404145078E-23 Liter Atmosphere
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Category: energy
Conversion: Millielectron Volt to Liter Atmosphere
The base unit for energy is joules (Non-SI/Derived Unit)
[Millielectron Volt] symbol/abbrevation: (meV)
[Liter Atmosphere] symbol/abbrevation: (l atm)

How to convert Millielectron Volt to Liter Atmosphere (meV to l atm)?
1 meV = 1.5812287194671E-24 l atm.
28 x 1.5812287194671E-24 l atm = 4.4274404145078E-23 Liter Atmosphere.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Millielectron Volt (meV) is equal to 1.60218E-22 joules, while 1 Liter Atmosphere (l atm) = 101.325 joules.
28 Millielectron Volt to common energy units
28 meV = 4.486104E-21 joules (J)
28 meV = 4.486104E-24 kilojoules (kJ)
28 meV = 1.0722045889101E-21 calories (cal)
28 meV = 1.0722045889101E-24 kilocalories (kcal)
28 meV = 0.028 electron volt (eV)
28 meV = 1.24614E-24 watt hour (Wh)
28 meV = 0.001028983353151 atomic unit of energy (au)
28 meV = 1.0722045889101E-30 tons of TNT (tTNT)
28 meV = 3.3087805081213E-21 foot pound force (ft lbf)
28 meV = 4.486104E-14 ergs (ergs)
(Millielectron Volt) to (Liter Atmosphere) conversions

Millielectron Volt to random (energy units)

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