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Convert [Millielectron Volt] to [Liter Atmosphere], (meV to l atm)

ENERGY


3868664930 Millielectron Volt
= 6.117244093311E-15 Liter Atmosphere
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Category: energy
Conversion: Millielectron Volt to Liter Atmosphere
The base unit for energy is joules (Non-SI/Derived Unit)
[Millielectron Volt] symbol/abbrevation: (meV)
[Liter Atmosphere] symbol/abbrevation: (l atm)

How to convert Millielectron Volt to Liter Atmosphere (meV to l atm)?
1 meV = 1.5812287194671E-24 l atm.
3868664930 x 1.5812287194671E-24 l atm = 6.117244093311E-15 Liter Atmosphere.
Always check the results; rounding errors may occur.

Definition:
In relation to the base unit of [energy] => (joules), 1 Millielectron Volt (meV) is equal to 1.60218E-22 joules, while 1 Liter Atmosphere (l atm) = 101.325 joules.
3868664930 Millielectron Volt to common energy units
3868664930 meV = 6.1982975775474E-13 joules (J)
3868664930 meV = 6.1982975775474E-16 kilojoules (kJ)
3868664930 meV = 1.481428675322E-13 calories (cal)
3868664930 meV = 1.481428675322E-16 kilocalories (kcal)
3868664930 meV = 3868664.93 electron volt (eV)
3868664930 meV = 1.7217493270965E-16 watt hour (Wh)
3868664930 meV = 142171.1361389 atomic unit of energy (au)
3868664930 meV = 1.481428675322E-22 tons of TNT (tTNT)
3868664930 meV = 4.5716296831559E-13 foot pound force (ft lbf)
3868664930 meV = 6.1982975775474E-6 ergs (ergs)
(Millielectron Volt) to (Liter Atmosphere) conversions

Millielectron Volt to random (energy units)

Random [energy unit] conversions